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प्रश्न
Express the following in terms of angles between 0° and 45°:
cos74° + sec67°
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उत्तर
cos74° + sec67°
= cos(90 - 16)° + sec(90 - 23)°
= sin16° + cosec23°
संबंधित प्रश्न
`(\text{i})\text{ }\frac{\cot 54^\text{o}}{\tan36^\text{o}}+\frac{\tan 20^\text{o}}{\cot 70^\text{o}}-2`
solve.
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