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प्रश्न
Express the following in term of angles between 0° and 45° :
cos 74° + sec 67°
बेरीज
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उत्तर
cos 74° + sec 67°
= cos(90° – 16°) + sec(90° – 23°)
= sin 16° + cosec 23°
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पाठ 21: Trigonometrical Identities - Exercise 21 (C) [पृष्ठ ३२८]
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