Advertisements
Advertisements
प्रश्न
Express the following in term of angles between 0° and 45° :
cosec 68° + cot 72°
Advertisements
उत्तर
cosec 68° + cot 72°
= cosec(90° – 22°) + cot(90° – 18°) ...(∵ cosec(90° – θ) = sec θ and cot(90° – θ) = tan θ)
= sec 22° + tan 18°
APPEARS IN
संबंधित प्रश्न
If `cosθ=1/sqrt(2)`, where θ is an acute angle, then find the value of sinθ.
Without using trigonometric tables evaluate the following:
`(i) sin^2 25º + sin^2 65º `
if `sqrt3 tan theta = 3 sin theta` find the value of `sin^2 theta - cos^2 theta`
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
Find the value of x, if sin x = sin 60° cos 30° + cos 60° sin 30°
Evaluate:
cos 40° cosec 50° + sin 50° sec 40°
Evaluate:
`(cos75^@)/(sin15^@) + (sin12^@)/(cos78^@) - (cos18^@)/(sin72^@)`
Prove that:
`1/(1 + cos(90^@ - A)) + 1/(1 - cos(90^@ - A)) = 2cosec^2(90^@ - A)`
If A and B are complementary angles, prove that:
cot B + cos B = sec A cos B (1 + sin B)
If \[\tan \theta = \frac{1}{\sqrt{7}}, \text{ then } \frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta} =\]
If \[\tan \theta = \frac{3}{4}\] then cos2 θ − sin2 θ =
\[\frac{2 \tan 30° }{1 + \tan^2 30°}\] is equal to
If A, B and C are interior angles of a triangle ABC, then \[\sin \left( \frac{B + C}{2} \right) =\]
tan 5° ✕ tan 30° ✕ 4 tan 85° is equal to
Evaluate: `(cos55°)/(sin 35°) + (cot 35°)/(tan 55°)`
Evaluate: 14 sin 30°+ 6 cos 60°- 5 tan 45°.
If sin θ + sin² θ = 1 then cos² θ + cos4 θ is equal ______.
If x and y are complementary angles, then ______.
Prove the following:
tan θ + tan (90° – θ) = sec θ sec (90° – θ)
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
