Question

Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)

Answer 1

Terminal arm passes through (4,3).

\[\therefore r = \sqrt{x^2 + y^2} = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5\]

Hence, 

\[\sin\theta = \frac{y}{r} = \frac{3}{5}\]