Advertisements
Advertisements
Question
Express the following in term of angles between 0° and 45° :
cos 74° + sec 67°
Advertisements
Solution
cos 74° + sec 67°
= cos(90° – 16°) + sec(90° – 23°)
= sin 16° + cosec 23°
RELATED QUESTIONS
Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.
if `sin theta = 1/sqrt2` find all other trigonometric ratios of angle θ.
if `tan theta = 1/sqrt2` find the value of `(cosec^2 theta - sec^2 theta)/(cosec^2 theta + cot^2 theta)`
Solve.
`cos55/sin35+cot35/tan55`
Evaluate.
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`
Show that : `sin26^circ/sec64^circ + cos26^circ/(cosec64^circ) = 1`
Express the following in terms of angles between 0° and 45°:
cosec68° + cot72°
For triangle ABC, show that : `tan (B + C)/2 = cot A/2`
Evaluate:
cosec (65° + A) – sec (25° – A)
Find the value of x, if sin x = sin 60° cos 30° – cos 60° sin 30°
Use tables to find cosine of 65° 41’
Use tables to find the acute angle θ, if the value of sin θ is 0.4848
If A + B = 90° and \[\tan A = \frac{3}{4}\]\[\tan A = \frac{3}{4}\] what is cot B?
The value of
In the following figure the value of cos ϕ is
A, B and C are interior angles of a triangle ABC. Show that
sin `(("B"+"C")/2) = cos "A"/2`
Evaluate: `(cot^2 41°)/(tan^2 49°) - 2 (sin^2 75°)/(cos^2 15°)`
Find the value of the following:
tan 15° tan 30° tan 45° tan 60° tan 75°
The value of the expression (cos2 23° – sin2 67°) is positive.
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
