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Question
Show that : `sin26^circ/sec64^circ + cos26^circ/(cosec64^circ) = 1`
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Solution
`sin26^circ/sec64^circ + cos26^circ/(cosec64^circ)`
= `sin26^circ/(sec(90^circ - 26^circ)) + cos26^circ/(cosec(90^circ - 26^circ))`
= `sin26^circ/(cosec26^circ) + cos26^circ/sec26^circ`
= sin226° + cos226°
= 1
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