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Question
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
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Solution
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
= `3 sin(90^circ - 18^circ)/(cos18^circ) - sec(90^circ - 58^circ)/(cosec58^circ)`
= `3 cos18^circ/(cos18^circ) - (cosec58^circ)/(cosec58^circ)`
= 3 – 1
= 2
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