Advertisements
Advertisements
प्रश्न
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Advertisements
उत्तर
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
= `3 sin(90^circ - 18^circ)/(cos18^circ) - sec(90^circ - 58^circ)/(cosec58^circ)`
= `3 cos18^circ/(cos18^circ) - (cosec58^circ)/(cosec58^circ)`
= 3 – 1
= 2
APPEARS IN
संबंधित प्रश्न
if `cot theta = sqrt3` find the value of `(cosec^2 theta + cot^2 theta)/(cosec^2 theta - sec^2 theta)`
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
What is the maximum value of \[\frac{1}{\sec \theta}\]
Write the value of tan 10° tan 15° tan 75° tan 80°?
If 5 tan θ − 4 = 0, then the value of \[\frac{5 \sin \theta - 4 \cos \theta}{5 \sin \theta + 4 \cos \theta}\] is:
If tan2 45° − cos2 30° = x sin 45° cos 45°, then x =
Prove that:
\[\left( \frac{\sin49^\circ}{\cos41^\circ} \right)^2 + \left( \frac{\cos41^\circ}{\sin49^\circ} \right)^2 = 2\]
A, B and C are interior angles of a triangle ABC. Show that
If ∠A = 90°, then find the value of tan`(("B+C")/2)`
Solve: 2cos2θ + sin θ - 2 = 0.
The value of cosec(70° + θ) – sec(20° − θ) + tan(65° + θ) – cot(25° − θ) is
