Advertisements
Advertisements
प्रश्न
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Advertisements
उत्तर
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
= `3 sin(90^circ - 18^circ)/(cos18^circ) - sec(90^circ - 58^circ)/(cosec58^circ)`
= `3 cos18^circ/(cos18^circ) - (cosec58^circ)/(cosec58^circ)`
= 3 – 1
= 2
संबंधित प्रश्न
Solve.
sin42° sin48° - cos42° cos48°
Express the following in terms of angle between 0° and 45°:
sin 59° + tan 63°
Find the value of angle A, where 0° ≤ A ≤ 90°.
sin (90° – 3A) . cosec 42° = 1
Use trigonometrical tables to find tangent of 37°
Write the maximum and minimum values of sin θ.
If 3 cot θ = 4, find the value of \[\frac{4 \cos \theta - \sin \theta}{2 \cos \theta + \sin \theta}\]
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
Find the value of the following:
`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`
If tan θ = cot 37°, then the value of θ is
`tan 47^circ/cot 43^circ` = 1
