Advertisements
Advertisements
प्रश्न
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Advertisements
उत्तर
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
= `3 sin(90^circ - 18^circ)/(cos18^circ) - sec(90^circ - 58^circ)/(cosec58^circ)`
= `3 cos18^circ/(cos18^circ) - (cosec58^circ)/(cosec58^circ)`
= 3 – 1
= 2
APPEARS IN
संबंधित प्रश्न
If tan A = cot B, prove that A + B = 90°.
Prove the following trigonometric identities.
(cosecA − sinA) (secA − cosA) (tanA + cotA) = 1
if `tan theta = 12/5` find the value of `(1 + sin theta)/(1 -sin theta)`
if `cot theta = sqrt3` find the value of `(cosec^2 theta + cot^2 theta)/(cosec^2 theta - sec^2 theta)`
A triangle ABC is right angles at B; find the value of`(secA.cosecC - tanA.cotC)/sinB`
Evaluate:
3 cos 80° cosec 10° + 2 cos 59° cosec 31°
Prove that:
tan (55° - A) - cot (35° + A)
If x sin (90° − θ) cot (90° − θ) = cos (90° − θ), then x =
If x tan 45° cos 60° = sin 60° cot 60°, then x is equal to
Express the following in term of angles between 0° and 45° :
sin 59° + tan 63°
