Advertisements
Advertisements
प्रश्न
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Advertisements
उत्तर
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
= `3 sin(90^circ - 18^circ)/(cos18^circ) - sec(90^circ - 58^circ)/(cosec58^circ)`
= `3 cos18^circ/(cos18^circ) - (cosec58^circ)/(cosec58^circ)`
= 3 – 1
= 2
संबंधित प्रश्न
If `cot theta = 1/sqrt3` find the value of `(1 - cos^2 theta)/(2 - sin^2 theta)`
Evaluate:
`2 tan57^circ/(cot33^circ) - cot70^circ/(tan20^circ) - sqrt(2) cos45^circ`
Find the value of x, if sin 3x = 2 sin 30° cos 30°
Use tables to find cosine of 8° 12’
Find the sine ratio of θ in standard position whose terminal arm passes through (3, 4)
If \[\tan \theta = \frac{3}{4}\] then cos2 θ − sin2 θ =
If 3 cos θ = 5 sin θ, then the value of
In the following figure the value of cos ϕ is
If ∆ABC is right angled at C, then the value of cos (A + B) is ______.
Find the value of the following:
tan 15° tan 30° tan 45° tan 60° tan 75°
