Advertisements
Advertisements
प्रश्न
Evaluate:
3 cos 80° cosec 10°+ 2 sin 59° sec 31°
Advertisements
उत्तर
3 cos 80° cosec 10° + 2 sin 59° sec 31°
= 3 cos 80° cosec (90° – 80°) + 2 sin 59° sec (90° – 59°)
= 3 cos 80° sec 80° + 2 sin 59° cosec 59°
= 3 × 1 + 2 × 1 ...(∵ cos A × sec A = 1)
= 3 + 2
= 5
APPEARS IN
संबंधित प्रश्न
If the angle θ= –60º, find the value of cosθ.
If tan A = cot B, prove that A + B = 90°.
Evaluate `(tan 26^@)/(cot 64^@)`
Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA
Evaluate.
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`
Express the following in terms of angle between 0° and 45°:
sin 59° + tan 63°
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
Use tables to find sine of 62° 57'
Use tables to find cosine of 8° 12’
Evaluate:
cos 40° cosec 50° + sin 50° sec 40°
Evaluate:
`(3sin72^@)/(cos18^@) - sec32^@/(cosec58^@)`
Prove that:
tan (55° - A) - cot (35° + A)
If the angle θ = –45° , find the value of tan θ.
If \[\cos \theta = \frac{2}{3}\] find the value of \[\frac{\sec \theta - 1}{\sec \theta + 1}\]
If 5 tan θ − 4 = 0, then the value of \[\frac{5 \sin \theta - 4 \cos \theta}{5 \sin \theta + 4 \cos \theta}\] is:
If \[\tan \theta = \frac{3}{4}\] then cos2 θ − sin2 θ =
If x tan 45° cos 60° = sin 60° cot 60°, then x is equal to
The value of \[\frac{\tan 55°}{\cot 35°}\] + cot 1° cot 2° cot 3° .... cot 90°, is
The value of tan 1° tan 2° tan 3°…. tan 89° is
The value of (tan1° tan2° tan3° ... tan89°) is ______.
