Advertisements
Advertisements
Question
Evaluate:
3 cos 80° cosec 10°+ 2 sin 59° sec 31°
Advertisements
Solution
3 cos 80° cosec 10° + 2 sin 59° sec 31°
= 3 cos 80° cosec (90° – 80°) + 2 sin 59° sec (90° – 59°)
= 3 cos 80° sec 80° + 2 sin 59° cosec 59°
= 3 × 1 + 2 × 1 ...(∵ cos A × sec A = 1)
= 3 + 2
= 5
APPEARS IN
RELATED QUESTIONS
Evaluate:
14 sin 30° + 6 cos 60° – 5 tan 45°
Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°
Evaluate:
`2(tan35^@/cot55^@)^2 + (cot55^@/tan35^@)^2 - 3(sec40^@/(cosec50^@))`
Find A, if 0° ≤ A ≤ 90° and 2 cos2 A – 1 = 0
Find the sine ratio of θ in standard position whose terminal arm passes through (3, 4)
∠ACD is an exterior angle of Δ ABC. If ∠B = 40o, ∠A = 70o find ∠ACD.
Write the maximum and minimum values of cos θ.
Write the acute angle θ satisfying `sqrt(3) sin θ = cos θ`.
Evaluate: `3(sin72°)/(cos18°) - (sec32°)/("cosec"58°)`.
The value of (tan1° tan2° tan3° ... tan89°) is ______.
