Advertisements
Advertisements
Question
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
Advertisements
Solution
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
= `sec(90^@-64^@)sin64^@ + (cosec(90^@-57^@))/sec57^@`
= `cosec64^@sin64^@ + sec57^@/sec57^@`
= 1 + 1
= 2
RELATED QUESTIONS
Evaluate `(sin 18^@)/(cos 72^@)`
Evaluate cosec 31° − sec 59°
Prove the following trigonometric identities.
(cosecA − sinA) (secA − cosA) (tanA + cotA) = 1
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Evaluate:
`sin80^circ/(cos10^circ) + sin59^circ sec31^circ`
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
Evaluate: `2(tan57°)/(cot33°) - (cot70°)/(tan20°) - sqrt(2) cos 45°`
If sin A = `3/5` then show that 4 tan A + 3 sin A = 6 cos A
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.

The value of the expression (cos2 23° – sin2 67°) is positive.
