Advertisements
Advertisements
Question
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
Sum
Advertisements
Solution
sin 3A – 1 = 0
`=>` sin 3A = 1
We know sin 90° = 1
∴ 3A = 90°
Hence, A = 30°
shaalaa.com
Is there an error in this question or solution?
Chapter 21: Trigonometrical Identities - Exercise 21 (E) [Page 333]
APPEARS IN
RELATED QUESTIONS
Solve.
sin15° cos75° + cos15° sin75°
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
Evaluate:
tan(55° - A) - cot(35° + A)
Use tables to find cosine of 8° 12’
Evaluate:
`2(tan35^@/cot55^@)^2 + (cot55^@/tan35^@)^2 - 3(sec40^@/(cosec50^@))`
If 3 cot θ = 4, find the value of \[\frac{4 \cos \theta - \sin \theta}{2 \cos \theta + \sin \theta}\]
Evaluate: `3(sin72°)/(cos18°) - (sec32°)/("cosec"58°)`.
If cot (90 – A) = 1, then ∠A = ?
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.
