Advertisements
Advertisements
प्रश्न
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
योग
Advertisements
उत्तर
sin 3A – 1 = 0
`=>` sin 3A = 1
We know sin 90° = 1
∴ 3A = 90°
Hence, A = 30°
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 21: Trigonometrical Identities - Exercise 21 (E) [पृष्ठ ३३३]
APPEARS IN
संबंधित प्रश्न
Solve.
sin15° cos75° + cos15° sin75°
Evaluate.
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`
Evaluate.
`(cos^2 32^@+cos^2 58^@)/(sin^2 59^@+sin^2 31^@)`
Use tables to find sine of 47° 32'
Use tables to find cosine of 2° 4’
Use trigonometrical tables to find tangent of 17° 27'
Use tables to find the acute angle θ, if the value of cos θ is 0.9848
If A and B are complementary angles, prove that:
`(sinA + sinB)/(sinA - sinB) + (cosB - cosA)/(cosB + cosA) = 2/(2sin^2A - 1)`
Write the value of cos 1° cos 2° cos 3° ....... cos 179° cos 180°.
Prove that `(tan A)/(cot A) = (sec^2A)/("cosec"^2A)`.
