Advertisements
Advertisements
प्रश्न
The value of 3 sin 70° sec 20° + 2 sin 49° sec 51° is
विकल्प
2
3
5
6
Advertisements
उत्तर
5
Explanation;
Hint:
3 sin 70° sec 20° + 2 sin 49° sec 51°
= `(3 sin 70°)/(cos (90 - 70°)) + (2 sin 49°)/(cos (90 - 49°))`
= `3 sin 70^circ/sin 70^circ + 2 sin 49^circ/sin 49^circ`
= 3 + 2
= 5
APPEARS IN
संबंधित प्रश्न
Without using trigonometric tables evaluate:
`(sin 65^@)/(cos 25^@) + (cos 32^@)/(sin 58^@) - sin 28^2. sec 62^@ + cosec^2 30^@`
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
If \[\tan \theta = \frac{3}{4}\] then cos2 θ − sin2 θ =
\[\frac{2 \tan 30° }{1 + \tan^2 30°}\] is equal to ______.
If sin θ =7/25, where θ is an acute angle, find the value of cos θ.
Express the following in term of angles between 0° and 45° :
cosec 68° + cot 72°
Evaluate: `(cot^2 41°)/(tan^2 49°) - 2 (sin^2 75°)/(cos^2 15°)`
Solve: 2cos2θ + sin θ - 2 = 0.
Find the value of the following:
tan 15° tan 30° tan 45° tan 60° tan 75°
If tan θ = cot 37°, then the value of θ is
