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Find A, if 0° ≤ A ≤ 90° and 4 sin2 A – 3 = 0

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Question

Find A, if 0° ≤ A ≤ 90° and 4 sin2 A – 3 = 0

Sum
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Solution

4 sin2 A – 3 = 0

`=> sin^2A = 3/4`

`=> sin A = sqrt(3)/2`

We know `sin 60^circ = sqrt(3)/2`

Hence, A = 60°

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Chapter 21: Trigonometrical Identities - TEST YOURSELF [Page 342]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 21 Trigonometrical Identities
TEST YOURSELF | Q 9. (iii) | Page 342
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