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प्रश्न
Find A, if 0° ≤ A ≤ 90° and 4 sin2 A – 3 = 0
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उत्तर
4 sin2 A – 3 = 0
`=> sin^2A = 3/4`
`=> sin A = sqrt(3)/2`
We know `sin 60^circ = sqrt(3)/2`
Hence, A = 60°
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