Advertisements
Advertisements
Question
In the case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
cos(90° - A) · sec 77° = 1
Advertisements
Solution
cos (90° - A) · sec 77° = 1
⇒ cos(90° - A) = `1/(sec 77°)`
⇒ cos(90° - A) = cos 77°
⇒ 90° - A = 77°
⇒ - A = 77° - 90°
⇒ - A = - 13°
⇒ A = 13°
APPEARS IN
RELATED QUESTIONS
Evaluate `(tan 26^@)/(cot 64^@)`
Prove the following trigonometric identities.
`((1 + cot^2 theta) tan theta)/sec^2 theta = cot theta`
if `3 cos theta = 1`, find the value of `(6 sin^2 theta + tan^2 theta)/(4 cos theta)`
Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA
Find the value of angle A, where 0° ≤ A ≤ 90°.
sin (90° – 3A) . cosec 42° = 1
Prove that:
`1/(1 + cos(90^@ - A)) + 1/(1 - cos(90^@ - A)) = 2cosec^2(90^@ - A)`
If \[\tan \theta = \frac{4}{5}\] find the value of \[\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta}\]
If A and B are complementary angles, then
In the following figure the value of cos ϕ is
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
