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प्रश्न
In the case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
cos(90° - A) · sec 77° = 1
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उत्तर
cos (90° - A) · sec 77° = 1
⇒ cos(90° - A) = `1/(sec 77°)`
⇒ cos(90° - A) = cos 77°
⇒ 90° - A = 77°
⇒ - A = 77° - 90°
⇒ - A = - 13°
⇒ A = 13°
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