Advertisements
Advertisements
प्रश्न
Show that : `sin26^circ/sec64^circ + cos26^circ/(cosec64^circ) = 1`
Advertisements
उत्तर
`sin26^circ/sec64^circ + cos26^circ/(cosec64^circ)`
= `sin26^circ/(sec(90^circ - 26^circ)) + cos26^circ/(cosec(90^circ - 26^circ))`
= `sin26^circ/(cosec26^circ) + cos26^circ/sec26^circ`
= sin226° + cos226°
= 1
संबंधित प्रश्न
If tan A = cot B, prove that A + B = 90°.
Find the value of x, if sin x = sin 60° cos 30° – cos 60° sin 30°
Find the value of angle A, where 0° ≤ A ≤ 90°.
cos (90° – A) . sec 77° = 1
If \[\sec\theta = \frac{13}{12}\], find the values of other trigonometric ratios.
What is the maximum value of \[\frac{1}{\sec \theta}\]
If \[\frac{160}{3}\] \[\tan \theta = \frac{a}{b}, \text{ then } \frac{a \sin \theta + b \cos \theta}{a \sin \theta - b \cos \theta}\]
If 16 cot x = 12, then \[\frac{\sin x - \cos x}{\sin x + \cos x}\]
If 8 tan x = 15, then sin x − cos x is equal to
The value of
`tan 47^circ/cot 43^circ` = 1
