Advertisements
Advertisements
प्रश्न
If tan A = cot B, prove that A + B = 90°.
सिद्धांत
Advertisements
उत्तर
∵ tan A = cot B
tan A = tan (90° – B)
A = 90° – B
A + B = 90°. Proved
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 18: Trigonometric Ratios of Some Standard Angles and Complementary Angles - Exercise 18C [पृष्ठ ३८०]
APPEARS IN
संबंधित प्रश्न
if `cot theta = sqrt3` find the value of `(cosec^2 theta + cot^2 theta)/(cosec^2 theta - sec^2 theta)`
Solve.
sin42° sin48° - cos42° cos48°
Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA
Evaluate.
`cos^2 26^@+cos65^@sin26^@+tan36^@/cot54^@`
Show that : sin 42° sec 48° + cos 42° cosec 48° = 2
Find the value of x, if sin x = sin 60° cos 30° – cos 60° sin 30°
Evaluate:
cos 40° cosec 50° + sin 50° sec 40°
\[\frac{2 \tan 30° }{1 + \tan^2 30°}\] is equal to
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.

2(sin6 θ + cos6 θ) – 3(sin4 θ + cos4 θ) is equal to ______.
