Advertisements
Advertisements
प्रश्न
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
Advertisements
उत्तर
sin (90° = θ) = cos θ
cos (90° = θ) = sinθ
3 sin (90° - 80°) cosec 10° + 2 cos (90° - 59°) sec 31°
3 sin 10° cosec 10° + 2 cos 31° sec31°
sin θ cosecθ = 1, cos θ secθ = 1
3 + 2 = 5
संबंधित प्रश्न
Express each of the following in terms of trigonometric ratios of angles between 0º and 45º;
(i) cosec 69º + cot 69º
(ii) sin 81º + tan 81º
(iii) sin 72º + cot 72º
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°
Solve.
`cos55/sin35+cot35/tan55`
Evaluate.
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`
Evaluate.
cos225° + cos265° - tan245°
Evaluate:
tan(55° - A) - cot(35° + A)
Use tables to find the acute angle θ, if the value of sin θ is 0.3827
∠ACD is an exterior angle of Δ ABC. If ∠B = 40o, ∠A = 70o find ∠ACD.
If angles A, B, C to a ∆ABC from an increasing AP, then sin B =
The value of tan 72° tan 18° is
