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प्रश्न
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
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उत्तर
sin (90° = θ) = cos θ
cos (90° = θ) = sinθ
3 sin (90° - 80°) cosec 10° + 2 cos (90° - 59°) sec 31°
3 sin 10° cosec 10° + 2 cos 31° sec31°
sin θ cosecθ = 1, cos θ secθ = 1
3 + 2 = 5
संबंधित प्रश्न
if `tan theta = 1/sqrt2` find the value of `(cosec^2 theta - sec^2 theta)/(cosec^2 theta + cot^2 theta)`
Solve.
`tan47/cot43`
Find the value of x, if sin x = sin 60° cos 30° + cos 60° sin 30°
Prove that:
sin (28° + A) = cos (62° – A)
Prove that:
`1/(1 + sin(90^@ - A)) + 1/(1 - sin(90^@ - A)) = 2sec^2(90^@ - A)`
If \[\frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta}\] write the value of \[\frac{1 - \cos^2 \theta}{2 - \sin^2 \theta}\]
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
Find the value of the following:
`cot theta/(tan(90^circ - theta)) + (cos(90^circ - theta) tantheta sec(90^circ - theta))/(sin(90^circ - theta)cot(90^circ - theta)"cosec"(90^circ - theta))`
`tan 47^circ/cot 43^circ` = 1
Prove the following:
tan θ + tan (90° – θ) = sec θ sec (90° – θ)
