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प्रश्न
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
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उत्तर
sin (90° = θ) = cos θ
cos (90° = θ) = sinθ
3 sin (90° - 80°) cosec 10° + 2 cos (90° - 59°) sec 31°
3 sin 10° cosec 10° + 2 cos 31° sec31°
sin θ cosecθ = 1, cos θ secθ = 1
3 + 2 = 5
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