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प्रश्न
Evaluate:
cosec (65° + A) – sec (25° – A)
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उत्तर
cosec (65° + A) – sec (25° – A)
= cosec [90° – (25° – A)] – sec (25° – A)
= sec (25° – A) – sec (25° – A)
= 0
संबंधित प्रश्न
Express each of the following in terms of trigonometric ratios of angles between 0º and 45º;
(i) cosec 69º + cot 69º
(ii) sin 81º + tan 81º
(iii) sin 72º + cot 72º
If tan A = cot B, prove that A + B = 90°.
Express the trigonometric ratios sin A, sec A and tan A in terms of cot A.
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Use tables to find the acute angle θ, if the value of tan θ is 0.7391
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cos 40° cosec 50° + sin 50° sec 40°
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`(cos75^@)/(sin15^@) + (sin12^@)/(cos78^@) - (cos18^@)/(sin72^@)`
Prove that:
\[\frac{sin\theta \cos(90° - \theta)cos\theta}{\sin(90° - \theta)} + \frac{cos\theta \sin(90° - \theta)sin\theta}{\cos(90° - \theta)}\]
2(sin6 θ + cos6 θ) – 3(sin4 θ + cos4 θ) is equal to ______.
