Advertisements
Advertisements
प्रश्न
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
Advertisements
उत्तर
From the tables, it is clear that cos 46° 30’ = 0.6884
cos q − cos 46° 30’ = 0.6885 − 0.6884 = 0.0001
From the tables, diff of 1’ = 0.0002
Hence, θ = 46° 30’ − 1’ = 46° 29’
APPEARS IN
संबंधित प्रश्न
Without using trigonometric tables evaluate the following:
`(i) sin^2 25º + sin^2 65º `
Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA
Express the following in terms of angle between 0° and 45°:
sin 59° + tan 63°
Evaluate:
`(sin35^circ cos55^circ + cos35^circ sin55^circ)/(cosec^2 10^circ - tan^2 80^circ)`
Use trigonometrical tables to find tangent of 17° 27'
If θ is an acute angle such that \[\tan^2 \theta = \frac{8}{7}\] then the value of \[\frac{\left( 1 + \sin \theta \right) \left( 1 - \sin \theta \right)}{\left( 1 + \cos \theta \right) \left( 1 - \cos \theta \right)}\]
The value of
Prove the following.
tan4θ + tan2θ = sec4θ - sec2θ
Express the following in term of angles between 0° and 45° :
cosec 68° + cot 72°
The value of the expression (cos2 23° – sin2 67°) is positive.
