Advertisements
Advertisements
प्रश्न
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
Advertisements
उत्तर
From the tables, it is clear that cos 46° 30’ = 0.6884
cos q − cos 46° 30’ = 0.6885 − 0.6884 = 0.0001
From the tables, diff of 1’ = 0.0002
Hence, θ = 46° 30’ − 1’ = 46° 29’
संबंधित प्रश्न
Prove the following trigonometric identities.
(cosecθ + sinθ) (cosecθ − sinθ) = cot2 θ + cos2θ
If `sqrt3 tan theta = 3 sin theta`, find the value of `sin^2 theta - cos^2 theta`
Use tables to find cosine of 65° 41’
If \[\tan A = \frac{5}{12}\] \[\tan A = \frac{5}{12}\] find the value of (sin A + cos A) sec A.
Prove that :
tan5° tan25° tan30° tan65° tan85° = \[\frac{1}{\sqrt{3}}\]
Evaluate:
3 cos 80° cosec 10°+ 2 sin 59° sec 31°
`(sin 75^circ)/(cos 15^circ)` = ?
2(sin6 θ + cos6 θ) – 3(sin4 θ + cos4 θ) is equal to ______.
The value of the expression (cos2 23° – sin2 67°) is positive.
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
