Advertisements
Advertisements
प्रश्न
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
Advertisements
उत्तर
From the tables, it is clear that cos 46° 30’ = 0.6884
cos q − cos 46° 30’ = 0.6885 − 0.6884 = 0.0001
From the tables, diff of 1’ = 0.0002
Hence, θ = 46° 30’ − 1’ = 46° 29’
संबंधित प्रश्न
If `cosθ=1/sqrt(2)`, where θ is an acute angle, then find the value of sinθ.
Evaluate:
`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`
Find the value of x, if sin x = sin 60° cos 30° – cos 60° sin 30°
Find the value of angle A, where 0° ≤ A ≤ 90°.
cos (90° – A) . sec 77° = 1
Use tables to find sine of 34° 42'
Use tables to find the acute angle θ, if the value of cos θ is 0.9848
Evaluate:
`(5sin66^@)/(cos24^@) - (2cot85^@)/(tan5^@)`
Evaluate:
3 cos 80° cosec 10° + 2 cos 59° cosec 31°
If \[\frac{160}{3}\] \[\tan \theta = \frac{a}{b}, \text{ then } \frac{a \sin \theta + b \cos \theta}{a \sin \theta - b \cos \theta}\]
Prove that `"tan A"/"cot A" = (sec^2"A")/("cosec"^2"A")`
