Advertisements
Advertisements
प्रश्न
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
Advertisements
उत्तर
From the tables, it is clear that cos 46° 30’ = 0.6884
cos q − cos 46° 30’ = 0.6885 − 0.6884 = 0.0001
From the tables, diff of 1’ = 0.0002
Hence, θ = 46° 30’ − 1’ = 46° 29’
APPEARS IN
संबंधित प्रश्न
If tan A = cot B, prove that A + B = 90°.
Express sin 67° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°
Show that cos 38° cos 52° − sin 38° sin 52° = 0
If `sqrt3 tan theta = 3 sin theta`, find the value of `sin^2 theta - cos^2 theta`
The value of tan 1° tan 2° tan 3° ...... tan 89° is
Prove that:
(sin θ + 1 + cos θ) (sin θ − 1 + cos θ) . sec θ cosec θ = 2
Evaluate: cos2 25° - sin2 65° - tan2 45°
Express the following in term of angles between 0° and 45° :
cos 74° + sec 67°
The value of the expression (cos2 23° – sin2 67°) is positive.
If x tan 60° cos 60°= sin 60° cot 60°, then x = ______.
