Advertisements
Advertisements
Question
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
Advertisements
Solution
From the tables, it is clear that cos 46° 30’ = 0.6884
cos q − cos 46° 30’ = 0.6885 − 0.6884 = 0.0001
From the tables, diff of 1’ = 0.0002
Hence, θ = 46° 30’ − 1’ = 46° 29’
RELATED QUESTIONS
Prove that:
`(cos(90^circ - theta)costheta)/cottheta = 1 - cos^2theta`
Use tables to find the acute angle θ, if the value of sin θ is 0.3827
If \[\tan \theta = \frac{4}{5}\] find the value of \[\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta}\]
If 5θ and 4θ are acute angles satisfying sin 5θ = cos 4θ, then 2 sin 3θ −\[\sqrt{3} \tan 3\theta\] is equal to
Prove the following.
tan4θ + tan2θ = sec4θ - sec2θ
Express the following in term of angles between 0° and 45° :
cosec 68° + cot 72°
Evaluate: `(sin 80°)/(cos 10°)`+ sin 59° sec 31°
In the case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
sin (90° - 3A).cosec 42° = 1.
Find the value of the following:
sin 21° 21′
`tan 47^circ/cot 43^circ` = 1
