Advertisements
Advertisements
प्रश्न
Use tables to find the acute angle θ, if the value of cos θ is 0.9574
Advertisements
उत्तर
From the tables, it is clear that cos 16° 48’ = 0.9573
cos θ − cos 16° 48’ = 0.9574 − 0.9573 = 0.0001
From the tables, diff of 1’ = 0.0001
Hence, θ = 16° 48’ − 1’ = 16° 47’
APPEARS IN
संबंधित प्रश्न
Prove the following trigonometric identities.
`((1 + cot^2 theta) tan theta)/sec^2 theta = cot theta`
Prove the following trigonometric identities.
(cosecA − sinA) (secA − cosA) (tanA + cotA) = 1
if `tan theta = 3/4`, find the value of `(1 - cos theta)/(1 +cos theta)`
Evaluate:
3cos80° cosec10° + 2 sin59° sec31°
Evaluate:
tan(55° - A) - cot(35° + A)
Evaluate:
`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`
∠ACD is an exterior angle of Δ ABC. If ∠B = 40o, ∠A = 70o find ∠ACD.
If \[\frac{160}{3}\] \[\tan \theta = \frac{a}{b}, \text{ then } \frac{a \sin \theta + b \cos \theta}{a \sin \theta - b \cos \theta}\]
If x tan 45° cos 60° = sin 60° cot 60°, then x is equal to
Evaluate: `(sin 80°)/(cos 10°)`+ sin 59° sec 31°
