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प्रश्न
Evaluate: `(sin 80°)/(cos 10°)`+ sin 59° sec 31°
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उत्तर
`(sin 80°)/(cos 10°)`+ sin 59° sec 31°
= `sin(90° - 10°)/(cos 10°)` + sin (90° - 31°)sec 31°
= `(cos 10°)/(cos 10°) + (cos 31°)/(cos 31°)`
= 1 + 1
= 2
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