Advertisements
Advertisements
प्रश्न
Find the value of x, if sin x = sin 60° cos 30° + cos 60° sin 30°
Advertisements
उत्तर
sin x = sin 60° cos 30° + cos 60° sin 30°
sin x = `(sqrt3/2)(sqrt3/2) + (1/2)(1/2)`
sin x = `3/4 + 1/4 = 1 = sin 90^circ`
Hence, x = 90°
संबंधित प्रश्न
Without using trigonometric tables evaluate the following:
`(i) sin^2 25º + sin^2 65º `
Write all the other trigonometric ratios of ∠A in terms of sec A.
Evaluate.
sin235° + sin255°
Evaluate:
`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`
If \[\tan \theta = \frac{1}{\sqrt{7}}, \text{ then } \frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta} =\]
If x tan 45° cos 60° = sin 60° cot 60°, then x is equal to
If 5θ and 4θ are acute angles satisfying sin 5θ = cos 4θ, then 2 sin 3θ −\[\sqrt{3} \tan 3\theta\] is equal to
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
In the case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
cos(90° - A) · sec 77° = 1
If ∠A = 30°, then tan 2A = ?
