Advertisements
Advertisements
प्रश्न
Use trigonometrical tables to find tangent of 17° 27'
Advertisements
उत्तर
tan 17° 27' = tan (17° 24' + 3')
= 0.3134 + 0.0010
= 0.3144
APPEARS IN
संबंधित प्रश्न
`\text{Evaluate }\frac{\tan 65^\circ }{\cot 25^\circ}`
Without using trigonometric tables, evaluate the following:
`( i)\frac{\cos37^\text{o}}{\sin53^\text{o}}\text{ }(ii)\frac{\sin41^\text{o}}{\cos 49^\text{o}}(iii)\frac{\sin30^\text{o}17'}{\cos59^\text{o}\43'}`
Evaluate:
`(cot^2 41^circ)/(tan^2 49^circ) - 2 sin^2 75^circ/cos^2 15^circ`
Evaluate:
`cos70^circ/(sin20^circ) + cos59^circ/(sin31^circ) - 8 sin^2 30^circ`
Find the value of x, if cos x = cos 60° cos 30° – sin 60° sin 30°
Find the value of x, if tan x = `(tan60^circ - tan30^circ)/(1 + tan60^circ tan30^circ)`
Use tables to find the acute angle θ, if the value of cos θ is 0.9574
If \[\cos \theta = \frac{2}{3}\] find the value of \[\frac{\sec \theta - 1}{\sec \theta + 1}\]
In the following figure the value of cos ϕ is

2(sin6 θ + cos6 θ) – 3(sin4 θ + cos4 θ) is equal to ______.
