Advertisements
Advertisements
प्रश्न
Express the following in terms of angle between 0° and 45°:
sin 59° + tan 63°
Advertisements
उत्तर
sin 59° + tan 63°
= sin(90 - 31)° + tan(90 - 27)°
= cos 31° + cot 27°
संबंधित प्रश्न
Prove the following trigonometric identities.
(cosecθ + sinθ) (cosecθ − sinθ) = cot2 θ + cos2θ
If `tan theta = 1/sqrt2` find the value of `(cosec^2 theta - sec^2 theta)/(cosec^2 theta + cot^2 theta)`
If `3 cos theta = 1`, find the value of `(6 sin^2 theta + tan^2 theta)/(4 cos theta)`
solve.
cos240° + cos250°
Use tables to find cosine of 9° 23’ + 15° 54’
If A and B are complementary angles, prove that:
cosec2 A + cosec2 B = cosec2 A cosec2 B
If 16 cot x = 12, then \[\frac{\sin x - \cos x}{\sin x + \cos x}\]
The value of cos2 17° − sin2 73° is
A, B and C are interior angles of a triangle ABC. Show that
If ∠A = 90°, then find the value of tan`(("B+C")/2)`
Prove that `(tan A)/(cot A) = (sec^2A)/("cosec"^2A)`.
