Advertisements
Advertisements
प्रश्न
Express the following in terms of angle between 0° and 45°:
sin 59° + tan 63°
Advertisements
उत्तर
sin 59° + tan 63°
= sin(90 - 31)° + tan(90 - 27)°
= cos 31° + cot 27°
संबंधित प्रश्न
Without using trigonometric tables, evaluate the following:
`( i)\frac{\cos37^\text{o}}{\sin53^\text{o}}\text{ }(ii)\frac{\sin41^\text{o}}{\cos 49^\text{o}}(iii)\frac{\sin30^\text{o}17'}{\cos59^\text{o}\43'}`
For triangle ABC, show that: `sin (A + B)/2 = cos C/2`
Find the value of x, if sin x = sin 60° cos 30° + cos 60° sin 30°
Use tables to find the acute angle θ, if the value of sin θ is 0.4848
Use tables to find the acute angle θ, if the value of tan θ is 0.7391
Evaluate:
3 cos 80° cosec 10° + 2 cos 59° cosec 31°
Prove that:
`1/(1 + sin(90^@ - A)) + 1/(1 - sin(90^@ - A)) = 2sec^2(90^@ - A)`
If \[\tan \theta = \frac{1}{\sqrt{7}}, \text{ then } \frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta} =\]
If tan2 45° − cos2 30° = x sin 45° cos 45°, then x =
If A + B = 90°, then \[\frac{\tan A \tan B + \tan A \cot B}{\sin A \sec B} - \frac{\sin^2 B}{\cos^2 A}\]
