Advertisements
Advertisements
Question
Express the following in terms of angle between 0° and 45°:
sin 59° + tan 63°
Sum
Advertisements
Solution
sin 59° + tan 63°
= sin(90 - 31)° + tan(90 - 27)°
= cos 31° + cot 27°
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Write all the other trigonometric ratios of ∠A in terms of sec A.
Use trigonometrical tables to find tangent of 42° 18'
Evaluate:
`sec26^@ sin64^@ + (cosec33^@)/sec57^@`
Prove that:
tan (55° - A) - cot (35° + A)
Prove that:
sin (28° + A) = cos (62° – A)
Prove that:
`1/(1 + sin(90^@ - A)) + 1/(1 - sin(90^@ - A)) = 2sec^2(90^@ - A)`
∠ACD is an exterior angle of Δ ABC. If ∠B = 40o, ∠A = 70o find ∠ACD.
The value of tan 10° tan 15° tan 75° tan 80° is
The value of 3 sin 70° sec 20° + 2 sin 49° sec 51° is
Sin 2B = 2 sin B is true when B is equal to ______.
