Advertisements
Advertisements
Question
Use trigonometrical tables to find tangent of 42° 18'
Numerical
Advertisements
Solution
tan 42° 18' = 0.9099
shaalaa.com
Is there an error in this question or solution?
Chapter 21: Trigonometrical Identities - Exercise 21 (D) [Page 331]
APPEARS IN
RELATED QUESTIONS
If tan 2θ = cot (θ + 6º), where 2θ and θ + 6º are acute angles, find the value of θ
Show that cos 38° cos 52° − sin 38° sin 52° = 0
solve.
sec2 18° - cot2 72°
Find the value of x, if sin x = sin 60° cos 30° – cos 60° sin 30°
Use tables to find sine of 62° 57'
If 16 cot x = 12, then \[\frac{\sin x - \cos x}{\sin x + \cos x}\]
The value of \[\frac{\cos^3 20°- \cos^3 70°}{\sin^3 70° - \sin^3 20°}\]
Prove that:
\[\left( \frac{\sin49^\circ}{\cos41^\circ} \right)^2 + \left( \frac{\cos41^\circ}{\sin49^\circ} \right)^2 = 2\]
Express the following in term of angles between 0° and 45° :
cosec 68° + cot 72°
Prove the following:
tan θ + tan (90° – θ) = sec θ sec (90° – θ)
