Advertisements
Advertisements
Question
Use tables to find sine of 62° 57'
Numerical
Advertisements
Solution
sin 62° 57' = sin (62° 54' + 3')
= 0.8902 + 0.0004
= 0.8906
shaalaa.com
Is there an error in this question or solution?
Chapter 21: Trigonometrical Identities - Exercise 21 (D) [Page 331]
APPEARS IN
RELATED QUESTIONS
If the angle θ= –60º, find the value of cosθ.
Show that cos 38° cos 52° − sin 38° sin 52° = 0
Prove the following trigonometric identities.
(secθ + cosθ) (secθ − cosθ) = tan2θ + sin2θ
if `cosec A = sqrt2` find the value of `(2 sin^2 A + 3 cot^2 A)/(4(tan^2 A - cos^2 A))`
Evaluate.
sin235° + sin255°
Evaluate:
`2 tan57^circ/(cot33^circ) - cot70^circ/(tan20^circ) - sqrt(2) cos45^circ`
Use tables to find sine of 34° 42'
The value of \[\frac{\tan 55°}{\cot 35°}\] + cot 1° cot 2° cot 3° .... cot 90°, is
Without using trigonometric tables, prove that:
sec70° sin20° + cos20° cosec70° = 2
If tan θ = cot 37°, then the value of θ is
