Advertisements
Advertisements
प्रश्न
Use tables to find sine of 62° 57'
संख्यात्मक
Advertisements
उत्तर
sin 62° 57' = sin (62° 54' + 3')
= 0.8902 + 0.0004
= 0.8906
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
संबंधित प्रश्न
`\text{Evaluate }\frac{\tan 65^\circ }{\cot 25^\circ}`
Evaluate.
sin(90° - A) cosA + cos(90° - A) sinA
Use tables to find the acute angle θ, if the value of cos θ is 0.9574
Find A, if 0° ≤ A ≤ 90° and cos2 A – cos A = 0
If \[\frac{x {cosec}^2 30°\sec^2 45°}{8 \cos^2 45° \sin^2 60°} = \tan^2 60° - \tan^2 30°\]
The value of tan 1° tan 2° tan 3° ...... tan 89° is
The value of cos 1° cos 2° cos 3° ..... cos 180° is
If A + B = 90°, then \[\frac{\tan A \tan B + \tan A \cot B}{\sin A \sec B} - \frac{\sin^2 B}{\cos^2 A}\]
Express the following in term of angles between 0° and 45° :
cos 74° + sec 67°
Solve: 2cos2θ + sin θ - 2 = 0.
