Advertisements
Advertisements
प्रश्न
Use tables to find sine of 47° 32'
Advertisements
उत्तर
sin 47° 32' = sin (47° 30' + 2')
= 0.7373 + 0.0004
= 0.7377
APPEARS IN
संबंधित प्रश्न
Express each of the following in terms of trigonometric ratios of angles between 0º and 45º;
(i) cosec 69º + cot 69º
(ii) sin 81º + tan 81º
(iii) sin 72º + cot 72º
Without using trigonometric tables, evaluate the following:
`(\sin ^{2}20^\text{o}+\sin^{2}70^\text{o})/(\cos ^{2}20^\text{o}+\cos ^{2}70^\text{o}}+\frac{\sin (90^\text{o}-\theta )\sin \theta }{\tan \theta }+\frac{\cos (90^\text{o}-\theta )\cos \theta }{\cot \theta }`
if `sqrt3 tan theta = 3 sin theta` find the value of `sin^2 theta - cos^2 theta`
Evaluate.
`cos^2 26^@+cos65^@sin26^@+tan36^@/cot54^@`
Use tables to find sine of 34° 42'
Use trigonometrical tables to find tangent of 37°
If \[\tan A = \frac{3}{4} \text{ and } A + B = 90°\] then what is the value of cot B?
If θ is an acute angle such that \[\tan^2 \theta = \frac{8}{7}\] then the value of \[\frac{\left( 1 + \sin \theta \right) \left( 1 - \sin \theta \right)}{\left( 1 + \cos \theta \right) \left( 1 - \cos \theta \right)}\]
If angles A, B, C to a ∆ABC from an increasing AP, then sin B =
In ∆ABC, `sqrt(2)`AC = BC, sin A = 1, sin2A + sin2B + sin2C = 2, then ∠A = ?, ∠B = ?, ∠C = ?
