Advertisements
Advertisements
प्रश्न
Find A, if 0° ≤ A ≤ 90° and 2 cos2 A + cos A – 1 = 0
Advertisements
उत्तर
2 cos2 A + cos A – 1 = 0
`=>` 2 cos2 A + 2 cos A – cos A – 1 = 0
`=>` 2 cos A (cos A + 1) – 1(cos A + 1) = 0
`=>` (2 cos A – 1)(cos A + 1) = 0
`=>` cos A = `1/2` or cos A = –1
We know `cos 60^circ = 1/2`
We also know that for no value of A(0° ≤ A ≤ 90°), cos A = –1.
Hence, A = 60°
APPEARS IN
संबंधित प्रश्न
if `3 cos theta = 1`, find the value of `(6 sin^2 theta + tan^2 theta)/(4 cos theta)`
Evaluate.
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`
Express the following in terms of angles between 0° and 45°:
cos74° + sec67°
Find the value of x, if cos (2x – 6) = cos2 30° – cos2 60°
Use tables to find the acute angle θ, if the value of tan θ is 0.4741
Write the maximum and minimum values of cos θ.
The value of
Express the following in term of angles between 0° and 45° :
cos 74° + sec 67°
If tan θ = 1, then sin θ . cos θ = ?
In the given figure, if AB = 14 cm, BD = 10 cm and DC = 8 cm, then the value of tan B is ______.

