Advertisements
Advertisements
प्रश्न
Find A, if 0° ≤ A ≤ 90° and cos2 A – cos A = 0
Advertisements
उत्तर
cos2 A – cos A = 0
`=>` cos A (cos A – 1) = 0
`=>` cos A = 0 or cos A = 1
We know cos 90° = 0 and cos 0° = 1
Hence, A = 90° or 0°
संबंधित प्रश्न
Without using trigonometric tables, evaluate the following:
`( i)\frac{\cos37^\text{o}}{\sin53^\text{o}}\text{ }(ii)\frac{\sin41^\text{o}}{\cos 49^\text{o}}(iii)\frac{\sin30^\text{o}17'}{\cos59^\text{o}\43'}`
if `tan theta = 1/sqrt2` find the value of `(cosec^2 theta - sec^2 theta)/(cosec^2 theta + cot^2 theta)`
Find the value of x, if cos (2x – 6) = cos2 30° – cos2 60°
Evaluate:
`2(tan35^@/cot55^@)^2 + (cot55^@/tan35^@)^2 - 3(sec40^@/(cosec50^@))`
The value of cos 1° cos 2° cos 3° ..... cos 180° is
In the following Figure. AD = 4 cm, BD = 3 cm and CB = 12 cm, find the cot θ.
Express the following in term of angles between 0° and 45° :
cos 74° + sec 67°
Evaluate: `(sin 80°)/(cos 10°)`+ sin 59° sec 31°
The value of 3 sin 70° sec 20° + 2 sin 49° sec 51° is
Prove the following:
tan θ + tan (90° – θ) = sec θ sec (90° – θ)
