Advertisements
Advertisements
प्रश्न
Find the value of x, if sin 3x = 2 sin 30° cos 30°
Advertisements
उत्तर
sin 3x = 2 sin 30° cos 30°
sin 3x = `2(1/2)(sqrt3/2)`
sin 3x = `sqrt3/2 = sin60^circ`
3x = 60°
Hence, x = 20°
संबंधित प्रश्न
If sin θ =3/5, where θ is an acute angle, find the value of cos θ.
Evaluate `(sin 18^@)/(cos 72^@)`
Evaluate:
`sin80^circ/(cos10^circ) + sin59^circ sec31^circ`
Prove that:
`(cos(90^circ - theta)costheta)/cottheta = 1 - cos^2theta`
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
If \[\frac{{cosec}^2 \theta - \sec^2 \theta}{{cosec}^2 \theta + \sec^2 \theta}\] write the value of \[\frac{1 - \cos^2 \theta}{2 - \sin^2 \theta}\]
In the following figure the value of cos ϕ is

Prove that:
\[\frac{sin\theta \cos(90° - \theta)cos\theta}{\sin(90° - \theta)} + \frac{cos\theta \sin(90° - \theta)sin\theta}{\cos(90° - \theta)}\]
Find the sine ratio of θ in standard position whose terminal arm passes through (4,3)
If cot( 90 – A ) = 1, then ∠A = ?
