Advertisements
Advertisements
Question
Find the value of x, if sin 3x = 2 sin 30° cos 30°
Advertisements
Solution
sin 3x = 2 sin 30° cos 30°
sin 3x = `2(1/2)(sqrt3/2)`
sin 3x = `sqrt3/2 = sin60^circ`
3x = 60°
Hence, x = 20°
APPEARS IN
RELATED QUESTIONS
If the angle θ = -60° , find the value of sinθ .
Without using trigonometric tables evaluate the following:
`(i) sin^2 25º + sin^2 65º `
If tan A = cot B, prove that A + B = 90°.
Prove the following trigonometric identities.
(secθ + cosθ) (secθ − cosθ) = tan2θ + sin2θ
Evaluate.
`cos^2 26^@+cos65^@sin26^@+tan36^@/cot54^@`
A triangle ABC is right angles at B; find the value of`(secA.cosecC - tanA.cotC)/sinB`
If 0° < A < 90°; find A, if `sinA/(secA - 1) + sinA/(secA + 1) = 2`
If A + B = 90° and \[\tan A = \frac{3}{4}\]\[\tan A = \frac{3}{4}\] what is cot B?
If x sin (90° − θ) cot (90° − θ) = cos (90° − θ), then x =
If y sin 45° cos 45° = tan2 45° – cos2 30°, then y = ______.
