Advertisements
Advertisements
Question
Prove that:
tan (55° - A) - cot (35° + A)
Advertisements
Solution
tan (55° - A) - cot (35° + A)
= tan [90° - (55° - A)] - cot (35° + A)
= cot (90° - 55° + A) - cot (35° + A)
= cot (35° + A) - cot (35° + A)
= 0
RELATED QUESTIONS
`(\text{i})\text{ }\frac{\cot 54^\text{o}}{\tan36^\text{o}}+\frac{\tan 20^\text{o}}{\cot 70^\text{o}}-2`
Show that : sin 42° sec 48° + cos 42° cosec 48° = 2
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Use tables to find the acute angle θ, if the value of sin θ is 0.6525
Use tables to find the acute angle θ, if the value of tan θ is 0.7391
Write the maximum and minimum values of sin θ.
The value of tan 10° tan 15° tan 75° tan 80° is
In the following figure the value of cos ϕ is
If tan θ = cot 37°, then the value of θ is
If sin θ + sin² θ = 1 then cos² θ + cos4 θ is equal ______.
