Advertisements
Advertisements
Question
Find the value of angle A, where 0° ≤ A ≤ 90°.
cos (90° – A) . sec 77° = 1
Sum
Advertisements
Solution
cos (90° – A) . sec 77° = 1
`sinA. 1/(cos77^circ) = 1`
sin A = cos 77°
= cos (90° – 13°)
= sin 13°
A = 13°
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
if `tan theta = 12/5` find the value of `(1 + sin theta)/(1 -sin theta)`
Solve.
`sec75/(cosec15)`
Evaluate.
`(2tan53^@)/(cot37^@)-cot80^@/tan10^@`
For triangle ABC, show that : `sin (A + B)/2 = cos C/2`
A triangle ABC is right angles at B; find the value of`(secA.cosecC - tanA.cotC)/sinB`
Use tables to find the acute angle θ, if the value of sin θ is 0.3827
Use tables to find the acute angle θ, if the value of cos θ is 0.9574
Prove that:
sec (70° – θ) = cosec (20° + θ)
Evaluate: `(cos55°)/(sin 35°) + (cot 35°)/(tan 55°)`
If tan θ = 1, then sin θ . cos θ = ?
