Advertisements
Advertisements
प्रश्न
Find the value of angle A, where 0° ≤ A ≤ 90°.
cos (90° – A) . sec 77° = 1
Advertisements
उत्तर
cos (90° – A) . sec 77° = 1
`sinA. 1/(cos77^circ) = 1`
sin A = cos 77°
= cos (90° – 13°)
= sin 13°
A = 13°
APPEARS IN
संबंधित प्रश्न
Solve.
`sec75/(cosec15)`
Solve.
sin42° sin48° - cos42° cos48°
Evaluate.
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`
A triangle ABC is right angles at B; find the value of`(secA.cosecC - tanA.cotC)/sinB`
Use tables to find sine of 34° 42'
Use tables to find the acute angle θ, if the value of cos θ is 0.6885
If \[\tan \theta = \frac{4}{5}\] find the value of \[\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta}\]
If 16 cot x = 12, then \[\frac{\sin x - \cos x}{\sin x + \cos x}\]
The value of cos 1° cos 2° cos 3° ..... cos 180° is
If sin θ + sin² θ = 1 then cos² θ + cos4 θ is equal ______.
