Advertisements
Advertisements
प्रश्न
Evaluate:
cos 40° cosec 50° + sin 50° sec 40°
Advertisements
उत्तर
cos 40° cosec 50° + sin 50° sec 40°
= cos (90° – 50°) cosec 50° + sin (90° – 40°) sec 40°
= sin 50° cosec 50° + cos 40° sec 40°
= 1 + 1
= 2
APPEARS IN
संबंधित प्रश्न
What is the value of (cos2 67° – sin2 23°)?
Prove the following trigonometric identities.
`((1 + cot^2 theta) tan theta)/sec^2 theta = cot theta`
if `tan theta = 3/4`, find the value of `(1 - cos theta)/(1 +cos theta)`
Evaluate:
`3 sin72^circ/(cos18^circ) - sec32^circ/(cosec58^circ)`
Use tables to find the acute angle θ, if the value of sin θ is 0.6525
Find A, if 0° ≤ A ≤ 90° and 2 cos2 A – 1 = 0
Write the value of tan 10° tan 15° tan 75° tan 80°?
If 16 cot x = 12, then \[\frac{\sin x - \cos x}{\sin x + \cos x}\]
If θ is an acute angle such that sec2 θ = 3, then the value of \[\frac{\tan^2 \theta - {cosec}^2 \theta}{\tan^2 \theta + {cosec}^2 \theta}\]
tan 5° ✕ tan 30° ✕ 4 tan 85° is equal to
