Advertisements
Advertisements
Question
Evaluate:
cos 40° cosec 50° + sin 50° sec 40°
Advertisements
Solution
cos 40° cosec 50° + sin 50° sec 40°
= cos (90° – 50°) cosec 50° + sin (90° – 40°) sec 40°
= sin 50° cosec 50° + cos 40° sec 40°
= 1 + 1
= 2
RELATED QUESTIONS
If the angle θ = -60° , find the value of sinθ .
Write all the other trigonometric ratios of ∠A in terms of sec A.
Evaluate.
`(sin77^@/cos13^@)^2+(cos77^@/sin13^@)-2cos^2 45^@`
Find the value of x, if cos (2x – 6) = cos2 30° – cos2 60°
Use tables to find the acute angle θ, if the value of tan θ is 0.7391
Prove that:
`1/(1 + cos(90^@ - A)) + 1/(1 - cos(90^@ - A)) = 2cosec^2(90^@ - A)`
If A and B are complementary angles, prove that:
cosec2 A + cosec2 B = cosec2 A cosec2 B
Find A, if 0° ≤ A ≤ 90° and 2 cos2 A – 1 = 0
`(sin 75^circ)/(cos 15^circ)` = ?
In ∆ABC, `sqrt(2)` AC = BC, sin A = 1, sin2A + sin2B + sin2C = 2, then ∠A = ? , ∠B = ?, ∠C = ?
