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प्रश्न
Prove that:
sec (70° – θ) = cosec (20° + θ)
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उत्तर
sec (70° – θ) = sec [90° – (20° + θ)] = cosec (20° + θ)
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संबंधित प्रश्न
Express each of the following in terms of trigonometric ratios of angles between 0º and 45º;
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(ii) sin 81º + tan 81º
(iii) sin 72º + cot 72º
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