Advertisements
Advertisements
प्रश्न
Prove that:
tan (55° + x) = cot (35° – x)
Advertisements
उत्तर
tan (55° + x) = tan [90° – (35° – x)] = cot (35° – x)
संबंधित प्रश्न
Prove the following trigonometric identities.
`(1 + sec theta)/sec theta = (sin^2 theta)/(1 - cos theta)`
`(tan^2theta)/((1+ tan^2 theta))+ cot^2 theta/((1+ cot^2 theta))=1`
If x = a cos θ and y = b sin θ, then b2x2 + a2y2 =
If m = a secA + b tanA and n = a tanA + b secA , prove that m2 - n2 = a2 - b2
Find x , if `cos(2x - 6) = cos^2 30^circ - cos^2 60^circ`
Prove that:
`(cot A - 1)/(2 - sec^2 A) = cot A/(1 + tan A)`
If cosθ + sinθ = `sqrt2` cosθ, show that cosθ - sinθ = `sqrt2` sinθ.
Choose the correct alternative:
Which is not correct formula?
If 1 + sin2α = 3 sinα cosα, then values of cot α are ______.
Complete the following activity to prove:
cotθ + tanθ = cosecθ × secθ
Activity: L.H.S. = cotθ + tanθ
= `cosθ/sinθ + square/cosθ`
= `(square + sin^2theta)/(sinθ xx cosθ)`
= `1/(sinθ xx cosθ)` ....... ∵ `square`
= `1/sinθ xx 1/cosθ`
= `square xx secθ`
∴ L.H.S. = R.H.S.
