Advertisements
Advertisements
प्रश्न
Use tables to find the acute angle θ, if the value of tan θ is 0.4741
Advertisements
उत्तर
From the tables, it is clear that tan 25° 18’ = 0.4727
tan θ − tan 25° 18’ = 0.4741 − 0.4727 = 0.0014
From the tables, diff of 4’ = 0.0014
Hence, θ = 25° 18’ + 4’ = 25° 22’
संबंधित प्रश्न
If tan 2θ = cot (θ + 6º), where 2θ and θ + 6º are acute angles, find the value of θ
if `sqrt3 tan theta = 3 sin theta` find the value of `sin^2 theta - cos^2 theta`
Evaluate.
`cot54^@/(tan36^@)+tan20^@/(cot70^@)-2`
Use tables to find sine of 10° 20' + 20° 45'
Use tables to find the acute angle θ, if the value of sin θ is 0.3827
If A and B are complementary angles, prove that:
cot A cot B – sin A cos B – cos A sin B = 0
Find A, if 0° ≤ A ≤ 90° and sin 3A – 1 = 0
If 0° < A < 90°; find A, if `(cos A )/(1 - sin A) + (cos A)/(1 + sin A) = 4`
If 5θ and 4θ are acute angles satisfying sin 5θ = cos 4θ, then 2 sin 3θ −\[\sqrt{3} \tan 3\theta\] is equal to
Evaluate: `(cot^2 41°)/(tan^2 49°) - 2 (sin^2 75°)/(cos^2 15°)`
